a cypher was released on thursday

My latest track was out on thursday but not yet online those who are on 4shared will be uploading it soon guys don’t worry it will be in your hands soon for more of my tracks check out my reverbnation @gideon and fb page @gideon c mwanza


back to scholl

Back in my school days, i
was sitting
in class one day and the
walked in. i decided to
jog with his mind and
asked him;
“How do you put an
elephant in the fridge?”
Teacher: I don’t know,
Me: You open the door
and put it in there!
Teacher: Oh! ok.
Me: How do you put a
donkey in the fridge?
Teacher: Ohh I
know this one, you open
door and put it in there,
Me: No, you open the
take the elephant out,
then you
put it in there.”
Teacher: (looking
Me: Let’s say all the
animals went to
the lion’s birthday party,
except one
animal, which one wud
it be?
Teacher: (a bit confused,
rolling eyes)….
The lion…..?
Me: No,the
donkey because it’s still
Teacher: u must be
Me: One last more
question, If there is a
river, en u know exactly
u usually see
it full of
crocodiles and you
wanted to
across it, how would
Teacher: You see, in this
case, there is no
other option, you would
to use the
Me: Lol, mscheww.. Sir,
swim across because all
crocodiles are at the
Sir, u can now do
what u came
here to do.
Teacher: Let’s call it a

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laws of physics

Work, Energy and Power
Work Done by a force is defined as the product of
the force and displacement (of its point of
application) in the direction of the force
W = F s cos θ
Negative work is said to be done by F if x or its
compo. is anti-parallel to F
If a variable force F produces a displacement in the
direction of F, the work done is determined from the
area under F-x graph. {May need to find area by
“counting the squares”. }
By Principle of Conservation of Energy,
Work Done on a system = KE gain + GPE gain +
Work done against friction}
Consider a rigid object of mass m that is initially at
rest. To accelerate it uniformly to a speed v, a
constant net force F is exerted on it, parallel to its
motion over a displacement s.
Since F is constant, acceleration is constant,
Therefore, using the equation:
v2 = u2 +2as,
as = 12 (v2 – u2)
Since kinetic energy is equal to the work done on the
mass to bring it from rest to a speed v,
The kinetic energy, EK = Work done by the force F
= Fs
= mas
= ½ m (v2 – u2)
Gravitational potential energy: this arises in a
system of masses where there are attractive
gravitational forces between them. The gravitational
potential energy of an object is the energy it
possesses by virtue of its position in a gravitational
Elastic potential energy: this arises in a system of
atoms where there are either attractive or repulsive
short-range inter-atomic forces between them.
Electric potential energy: this arises in a system of
charges where there are either attractive or repulsive
electric forces between them.
The potential energy, U, of a body in a force field
{whether gravitational or electric field} is related to
the force F it experiences by:
F = – dU / dx.
Consider an object of mass m being lifted vertically
by a force F, without acceleration, from a certain
height h 1 to a height h2. Since the object moves up
a constant speed, F is equal to mg.
The change in potential energy of the mass = Work
done by the force F
= F s
= F h
= m g h
Efficiency: The ratio of (useful) output energy of a
machine to the input energy.
Useful Output
Energy x100%
Useful Output
Power x100%
Input Energy Input Power
Power {instantaneous} is defined as the work done
per unit time.
Total Work
Done =W
Total Time t
Since work done W = F x s,
P = F x s = Fv t
for object moving at const speed: F = Total resistive
force {equilibrium condition}
for object beginning to accelerate: F = Total resistive
force + ma

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